test2.py

Created by stella-maestre

Created on November 05, 2020

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chap 3 mondeles ondulatoire et particulaire de la lumiere
longueur donde (y) en m=c/v (c en m.s-1, v en Hz)
Energie en E-> Ephoton=hxv=hxc/y
c=3,00 x108 m.s-1: la célérité de la lumière dans le vide
h=6,63 x10-34 J.s: la constante de Planck
1nm = 10-9m
1m=109nm
1GHz= 9Hz
1eV=1,60 x10-19J
1J=1/1,60 x10-19
triangleE= lEf-Eil=Ephoton=hxv=h c/y

chap 4 composition chimique des solutions
msolute en g; nsolute en mol; Vsolution en L; M masse molaire du solute en g.mol-1
n=m/M (liquide solide gaz)

M=m/n
n=pxv/M  (liquide)
 m/M
 
p=m/V (liquide)
n=V/Vm (gaz)
 
n= cxvsolution (soluté)

concentration en masse: Y= msoluté/vsolution en g.l-1
concentration molaire: C=nsoluté/vsolution mol.L-1

nmere=nfille donc Cmere x Vmere= Cfille x Vfille

A=ExLxC vaec E: le coef d'absorbtion molaire; L l'épaisseur de solution traversee en cm
diluée en concentration C

absorbance proportionelles a la concentration A=kxC

chap 5
si xf =xmax alors transformation totale
si xf<xmx zlotd transformation non totale
reaction dequation stoechiometrique= aA+bB->cC+dD
melange est dit stoechiometrique quand no(A)/a=no(B)/b

equation pour calculer x max
soit x reafctif limitant donc ...-...=0

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