exercice_5.py

Created on December 14, 2023

520 Bytes

3. y=f'(-1)(x-(-1))f(1)
Dn 
y=(-3(-12)+6(-1)(x+1)+-((-1)3)
+3((-1)2)+1
y=(-3 -6)(x+1)+1+3+1
y=-9(x+1)+5
y=-9x-4

5. y=f'(a)(x-a)+f(a)

y=(-3a2+6a)(x-a)+ -a3+3a2+1
y=(-3a2+6a)x+3a3-6a2- a3+3a2 + 1
y=(-3a2+6a)x+2a3-3a2+1

1. avec les nombres de dérivés

2. il faut donc trouver deux 
valeurs de x tel que f'(x)=0
f'(x)=-3x2+6x
f'(x)=0 = -3x2 + 6x = 0
 -3x2 + 6x = 0
x=0 ou -3x+6=0
x=0 ou x=2.
points de coordonnées 
(0,f(0)) et (2,f(2))
sachant que
f(0)=-(03)+3(02)+1=0
f(2)=-(23)+3(22)+1=-8+12+1=5

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