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convert number from one base to another base

Although micropython can do these convertions using int(), hex(), oct() and bin(). The convertion is coded in Python for fun.

There are two functions defined, first function converts from arbitrary base to base 10, second fucntion converts from base 10 to new base

• tobase10(s, base)
  • convert number to base 10
  • s: string representation of number
  • base: integer stating number base of s
  • returns: integer version of s in base 10
• frombase10(x, base)
  • convert number from base 10 to another base
  • x: integer representation of number
  • base: integer stating number base to convert to
  • returns: string representation of x in new base

# convert number from one base to another base

sym = [str(n) for n in range(0,10)]+[chr(n) for n in range(65,91)]
sym = "".join(sym)

# convert number to base 10
# s: string representation of number
# base: integer stating number base of s
# returns: integer version of s in base 10
def tobase10(s, base):
  x=0
  for n in range(len(s)):
    ch=s[len(s)-n-1].upper()
    pos=sym[:base].rfind(ch)
    if pos>-1:
      x+=pos*base**n
    else:
      raise Exception("Invalid symbol '{0}' in '{1}' for base {2}".format(ch,s,base))
  return x

# convert number from base 10 to another base
# x: integer representation of number
# base: integer stating number base to convert to
# returns: string representation of x in new base
def frombase10(x, base):
  if not 2<=base<=35:
    raise Exception("<Specified number base outside range of 2..{0}".format(len(sym)-1))
  q=x
  value=""
  while q>0:
    q,r=divmod(q,base)
    value=sym[r]+value
  return value

print("Convert number from\none base to another")
print("For example\nhexadicimal -> base 16\nbinary -> base 2\ndecimal base 10\noctal -> base 8")
base_from=int(input("current base of number? "))
n=input("number value in base {0}? ".format(base_from))
base_to=int(input("base to convert to? "))
n_b10=tobase10(n,base_from)
n_result=frombase10(n_b10,base_to)
print("\n{0} in base {1}\n = {2} in base {3}".format(n,base_from,n_result,base_to))
print(" = {0} in base 10".format(n_b10))