lateam.py

Created by tombachi445

Created on November 09, 2023

530 Bytes

un=u0xq^n
si sa commence a u1 alors un=u1xq^n-1
croisante si et seulement si q>1
constante si et seulement q=1
moyenne geometrique=multiplie les deux racines des nombre entre eux
somme des terme=
sigma(au dessus nombre de terme et en dessous k=0 ou 1)
u0 x 1-q^n/1-q
relation de recurrence= un+1=un+premier terme
sigma..nb terme x u0+dernierterme/2
moyenne aritmetique de 6 et 18= 6+18/2
evenement independants=
p(B∩S)=p(b)xp(s)
si pas egale entre eux alors independants
relation reccurence geometrique =*
un+1=unxq

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