conti.py

Created on December 08, 2021

506 Bytes

tout les polynomes sont continue sur R

Sur [inter] g possède un minimum qui vaut (la borne à gauche du tableau) donc
g(x)= le alpha n'admet pas de solution sur cet intervalle


TVI : 
  Sur [inter] g est continue et strictement croiss/décroiss
  De plus f(borne intervalle)= son image et f(borne intervalle)= son image
  Or val alpha appartient à l'inter image 
  Donc d'après le TVI, g(x)= le alpha admet une unique solut° sur [inter]

justifier asymptote à cf = on cherche limite en 0

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