wordle.py

Created on April 18, 2023
1.45 KB
The game of wordle! Note: enter a 5 letter word at the start or it will crash.
from kandinsky import fill_rect as rct,draw_string as txt
from ion import keydown
from time import sleep

KEYS=[18,"a",19,"b",20,"c",21,"d",22,"e",23,"f",24,"g",25,"h",26,"i",27,"j",28,"k",29,"l",30,"m",31,"n",32,"o",33,"p",34,"q",36,"r",37,"s",38,"t",39,"u",40,"v",42,"w",43,"x",44,"y",45,"z"]
WHT,GRY=(255,255,255),(200,200,200)

def dinput(x,y):
  a=""
  l=0
  while True:
    if keydown(17):
      a=a[:-1]
      l=17
    elif keydown(52)and len(a)==5:return a
    else:
      for i in range(len(KEYS)/2):
        if keydown(KEYS[i*2]):
          a+=KEYS[i*2+1]
          l=KEYS[i*2]
    a=a[:5]
    for i in range(5):
      try:txt(a[i],x+20*i,y,WHT,GRY)
      except:txt(" ",x+20*i,y,WHT,GRY)
    while keydown(l):pass
    l=0

def game():
  rct(110,60,100,120,GRY)
  for i in range(6):rct(i*20+109,60,2,120,(0,0,0))
  for i in range(7):rct(109,i*20+59,102,2,(0,0,0))
  txt("WORDLE",130,20)
  txt("By squarepoint",90,40)
  for i in range(6):
    txt("Try: "+str(i+1),220,70)
    while keydown(52):pass
    a=dinput(115,61+20*i)
    for j in range(5):
      if a[j]==WORD[j]:c=(0,200,0)
      elif a[j]in WORD:c=(200,200,0)
      else:c=(100,100,100)
      rct(111+20*j,61+20*i,18,18,c)
      txt(a[j],115+20*j,61+20*i,WHT,c)
    if a==WORD:
      txt("GG! You guessed the Wordle in",15,183)
      txt(str(i+1)+" tries!",120,203)
      break
  if not a==WORD:
    txt("You lost",120,183)
    txt("The Wordle was "+WORD,50,203)

WORD=input("Enter word: ")
game()