mpo_bonbons.py

Created by schraf

Created on March 05, 2022

616 Bytes

Enoncé de l’exercice

from math import ceil
from kandinsky import fill_rect
from random import randint

def affiche(l,c):
    m = max(c)  # maxi bonbons parmi les enfants
    for (i,v) in enumerate(c):
        coul = int(255 * v / m) # variation de la couleur rouge
        fill_rect(2*i, l, 2, 1, (coul,0,0)) # rectangle 2*1 pixels

def MPO106():
    t = 0
    Bo = [0 if k%4 == 0 else randint(1,200) for k in range(160)]    # initialisation repartition
    while max(Bo) != min(Bo):
        Bo = [ceil(b/2) + ceil(Bo[k-1]/2) for (k,b) in enumerate(Bo)]
        affiche(t, Bo)
        t += 1
    return Bo[0]

MPO106()

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