proba.py

Created on December 12, 2022

522 Bytes


loibinnomiale

X->B(n,p)

P(X=K) = (K parmi N) p^k (1-p)^n-k

E(X)=np
V(X)=npq

Experience avec 1 echec 1 succès à un rang donné

2) loi de Bernouilli

X-> B(p)

P(x=0)=1-p
P(X=1)=p

E(X)=P
V(x)=p(1-p)

Exp avec 1 echec et 1 succès


3) Loi de poisson

X-> P(phi)

P(X=k)= e^-lambda lambda^k/k

E(x)= lambda
V(x)= lambda

np<10
n>50
p<0,1

implication des heurre dans la consigne

4) loi geometrique


X-> G(p)

 P(X = n) = (1 − p)^n−1.p

E(x)=1/P
V(x)= 1-p/p^2

loi d'attente du rang du premier succès

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proba.py