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press the key whose number is printed in the currently appearing crate on the screen you have 5 seconds to break as many crates as you can (the countdown stops when there’s nothing to break)

be carfeful ! breaking a crate that isn’t shown will give you bad points !

from random import randint as rd
from ion import keydown as kd
from time import *
from kandinsky import fill_rect as fr, draw_string as ds

def play(ti=15,m=1,min=0,max=5):
  def sc(c=(255,)*3):
    fr(0,0,320,222,c)
  def hh(ha):
    return (42,43,44,36,37,38,30,31,32)[ha-1]
  def cc():
    return [16*rd(1,16)-1 for _ in range(3)]
  def tt(ta=0):
    b="{}/{}".format(u,v)
    ds(b,160-5*len(b),91)
    b=str(round(t,3))
    ds(b,160-5*len(b),111)
  def ovt(ooa=0):
    oox=89 if ooa<2 else 160
    if ooa%2==1:
      global u, o
      oob="{}/{}".format(u,o)
      ds(oob,160-5*len(oob),oox)
    global t
    oob=str(round(t,3))[:4]
    fr(160-40,oox+20,80,20,(255,)*3)
    ds(oob,160-5*len(oob),oox+20)
  
  def dd(dx,dy,dt):
    da=cc()
    fr(dx,dy,80,80,(0,)*3)
    fr(dx+5,dy+5,70,70,da)
    dt=str(dt)
    ds(dt,dx+40-(len(dt)*5),dy+30,(0,)*3,da)
  
  def ss(sa):
    ovt(3 if sa==5 else 1)
    global t
    dd(120*((sa-1)%3),142-71*((sa-1)//3),sa)
    while t>0:
      st=monotonic()
      ovt(2 if sa==5 else 0)
      for i in range(1,10):
        if kd(hh(i)):
          return True if sa==i else False
      t-=monotonic()-st
  
  global t, u, o
  u=0
  o=0
  t=float(ti)
  while t>0:
    sc()
    o+=1
    ovt(1)
    if m>0:
      sleep(rd(min*100,max*100)/100)
    
    if ss(rd(1,9)):
      u+=1
    
  sc()
  dd(20,71,"end!")
  dd(120,71,"{}/{}".format(u,o))
  dd(220,71,"end!")

print("play()")