deployment.py

Created by pianet-hugo-39

Created on November 21, 2021

655 Bytes

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prouver pour toute n  qu il est divisble par x
2k et 2k+1

par recurence:
intro avec P(0)
heredite:
  2**n-1=3q
  4*2**2n-1*4=4*3q
  2**2*2**2n-1-3=4*3q
  2**2n+2-1=4*3q+3
  2**2(n+1)-1=3(4q+1)
conclusion donc P(n) est vraie

z*Z=z+2
(a+bi)(a-bi)=a+bi+2
a**2+b**2=a+bi+2
a**2+b**2-a-2=bi

Je place:
  a**2+b**2-a-2=bi    bi=0 b=0
{  
  a**2+b**2-a-2=0
a**2+0**2-a-2=0

delta=(-1)**2-4*1*(-2)=9  
(1+racine9)/2*1=2
(1-racine9)/2*1=(-1)

a1 vaut 2 et a2 vaut (-1) 
donc z=2+0*i ou z=(-1)+0*i


(2+i)z=1+i-2iz
2z+iz+2iz=1+i
z(2+i+2i)1+i
z=(1+i)/(2+3i)=(1+i)*(2-3i)/(2+3i)(2-3i)
 =(2-3i+2i-3i**2)/2**2+3**2=(5-i)/13

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