exovision.py

Created by nolannoisette

Created on February 07, 2024

2.97 KB


Soit un couple oculaire age de 36 ans, caracteriser par :
OD : Rd = -4.00       H'R' = 22.1 mm
OG : R'G = 58         Dog = 60

1. Donnez la nature et le type de l'ametropie
   oeil
R -------) R'
    H;H'

Doeil = R'-R   avec R'=ncv/H'R' et Doeil = n'/H'F'

OD : Rd = -4.00   H'R'D = 22.1mm

R'D = ncv/H'R'D = 1.336/22.1x10 puissance -3 = 60.452
Dod = R'D-RD
Dod = 60.452-(-4)= 64.452

H'FD = ncv/Dod = 1.336/64.452 = 20.759mm

H'F'D<H'R'D : cest un oeil myope
H'R'D=H'R' theo (22.1mm)
Dod nest pas egale a Do theo (60)

--) Cest un oeil myope de puissance dune valeur de -4

OG : R'G = 58   Dog = 60

H'R'G = ncv/R'og = 1.336/58 = 23.034mm
H'F'G = ncv/Dog = 1.336/60 = 22.267mm

Dog = R'G-RG
RG = R'G-Dog
RG = 58-60 = -2

H'F'G<H'R'G cest un oeil myope 
H'R'G nest pas egale a H'R' theo (22.1mm)
Dog=Do theo (60)

--) cest une myopie axile dune valeur de -2


2. Donnez le type d'anisometropie de couple oculaire 

Rd nest pas egale a Rg
R'd nest pas egale a R'g
Dog nest pas egale a Dog

cest donc une anisometropie de conformation


3.On donne LH=13mm, calculez la compensation parfaite pour chaque oeil

     Dl         oeil
Rl -------) R -------) R'
           F'L  Acc=0

Dl = 1/LR - 1/LRL(=0)   avec LRL = infini
                            1/LRL = 0
Dl = 1/LR

OD : Rod = -4.00  avec R = 1/HR

HRD = 1/RD = 1/-4 = -250mm
LRD = LH + HRD
LRD = 13 + (-250) = -237mm

DLD = 1/LRD = 1/-237 x 10 puissance -3 = -4.219


OG : 
RG = -2

HRG = 1/RG = 1/-2 =-500mm
LRG = LH + HRG = 13 + (-500) = -487mm
DLG = 1/LRG = 1/-487 x 10 puissance -3 = -2.059


4.Determinez les parcours d'accomodation vrais et apparents de chaque oeil


Parcours vrai : 
D= R'-R
R= R'-D
R=1/HR

Aconf = R-C
C = R-Aconf 
C = 1/HC

Amax = R-P
P = R-Amax
P = 1/HP

Amax = 15 - age/4
Amax = 15 - 36/4
Amax = 6

Aconf = 1/2 de Amax
Aconf = 6/2 = 3

OD : 
RD = -4      HRD = -250mm
CD = -4-3 = -7
HCD = 1/CD = 1/-7 = -142.857mm

PD = RD-Amax
PD = -4-6 = -10
HPD = 1/PD = 1/-10 = -100mm


OG : 
RG = -2    HRG = -900mm
CG = RG - Aconf 
CG = -2-3 = -5
HCG = 1/CG = 1/-5 = -200mm


PG = RG-Amax
PG = -2-6 = -8
HPG = 1/PG = 1/-8 = -125mm



Parcours apparent : 
Dl = 1/LR-1/LRL
Dl = 1/LC-1/LCL
Dl = 1/LP-1/LPL


OD :
LRLD =infini et RLD = 0 car le compensateur est parfait

LCLD = LH + HCD = 13 + (-142.857) = -129.857mm

DLD = 1/LCD-LCLD
1/LCLD = 1/LCD-DLD
LCL = 1/(1/LCD-DLD) = 1/(1/-129.857 x 10 puissance -3-(-4.219)) = -287.209mm
CLD = 1/-287.209 x 10 puissance -3 = -3.482

LPD = LH + HPD = 13 + (-100) = -87mm
DLD = 1/LPD -DLD
LPLD = 1/(1/LPD - DLD) = 1/(1/-87 x 10 puissance -3-(-4.219)) = -137,452mm
PLD = 1/-137,452 x 10 puissance -3 = -7.179

OG :
LRLG =infini et RLG = 0 car le compensateur est parfait

LCLG = LH + HCG = 13 + (-200) = -187mm

LCLG = 1/(1/LCG-DL)
LCLG = 1/(1/-187 x 10 puissance -3-(-2.055)) = -303.517mm

CLG = 1/LCLG = 1/-303.527 x 10 puissance -3 = -3.294
LPG = LH + HPG = 13 + (-125) = -112mm
LPLG = 1/(1/LPG-DLG)
LPLG = 1/(1/-112 x 10 puissance -3 -(-2.053)) = -145.442mm
PLG = 1/LPLG = 1/-145.442 x 10 puissance -3 = -6.875

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