exerciceso.py

Created on February 15, 2024

472 Bytes

Exercice 1:
on donne n=1  n'=1.5  HF=30mm  HH'=5mm  AB=10mm

1. Calculer la taille de l'image A'B' si H'A'=50mm
D=(-n)/HF
D= (-1)/0,03
D=-33,333 dioptries

D=(n'/H'A')-(n/HA)
n/HA=(n'/H'A')-D
HA=n/((n'/H'A')-D)= 1/((1,5/0,05)-(-33,333))=0,016m = 16mm

Y= A'B'/AB=(n x H'A')/(n' x HA)
A'B'=(AB x n x H'A')/(n' x HA)
A'B'=(10 x 1 x 50)/(1,5 x 15,709)
A'B'=21,111mm

2. Calculer la taille de l'image A'B' si FA=10mm
A'B'/AB=-HF/FA
A'B'=(-30 x 10)/10 = -30mm

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