mecaacide.py

Created on January 23, 2022

561 Bytes

-meca
 energie cinetique=Ec=1/2m*v**2
en joules m=kg v=m/s
 energie potentielle=Ep=m*g*h
en joules g=9.81N/kg h=m
 energie meca= Ec+Ep

travail dune force=W=F*AB*cos(alfa)
F=force AB=longueur force cos(a)=angle force/longueur
travail moteur=alfa inf 90deg
travail resistant= alfa sup 90deg
Ecfinal-Ecintitial=theoreme energie cinetique

-acide/basique
acide=0 a 7  donne un proton H+
basique= 7 a 14 capte un proton H+
A+H=AH  A=base  AH=acide
couple acide base
HCI/CI-  CH3COOH/CH3COO-  NH4-/NH3
H3O+/H2O  HO-/H2O
ACIDE1+BASE2<=>BASE1+ACIDE2

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