vecteur.py

Created on December 21, 2023

490 Bytes

- produit scalaire 
u(1,4,5)  v(7,0,3)
U°v = (1x7+4x0+5x3)

- calcul coordonnées de deux points 
AB(xB-xA,yB-yA,zB-zA)

- produit vectoriel 
u(x,y,z) v(x',y',z')
1. determinant |i j k |
               |x y z |
               |x'y'z'|
2. u^v(uz'-zy',zx'-xz',xy'-yx')

- calcul valeur angle 
cos (AB,AC)= AB°AC/||AB||x||AC||
            produit scalaire/ racine i2+j2

(AB,AC)=Arcos( resultat )= en degres 

- si on nous donne un angle calcul scalaire
u°v=||u||x||v||xcos(u,v)

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