recurencelimite2.py

Created by math-pana72

Created on January 19, 2023

259 Bytes


Un+1=1/3Un+2 et U0=2

AnEN, Pn:Un<(egale)3

Initialisation
U0=2 2<3 donc P0 est vérifié

Heredité
soit kEN, supposons que Pk est vérifié: Uk<3
Uk<3
1/3Uk<1
1/3Uk+2<3
Uk+1<3
donc Pk+1 est vérifié

Conclusion
AnEN, Pn est vérifie

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