Question2:Calculezlaforcedefrictiondel'air (Ffair )
Tu isoles Ffair dans ton
équation précédente :
Ffair =m⋅g⋅sin(30∘)−Fsn
1. Calcul de la force
motrice (le poids sur l'axeX):Px=80⋅9,81⋅sin(30∘).Px=392,4N.2.Calculdufrottementskis-neige (Fsn):Laforcenormalesurunepentecorrespondàlacomposantedupoidssurl'axe Y :
N=m⋅g⋅cos(30∘).
Fsn =μc ⋅N
Fsn =0,05⋅80⋅9,81⋅cos(30∘).
Fsn =33,98 N.
3. Résultat final :
Ffair =392,4−33,98.
Ffair =358,42 N.
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