ex14.py

Created on March 18, 2026

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Question 4) Calculez la distance et 
le temps alors nécessaires 
pour s'arrêter.

On sait qu'elle part d'une 
vitesse initiale (v0 ) 
de 5 m/s pour arriver à une
vitesse finale (v) de 0 m/s 
(arrêt). L'accélération (a) 
est de −0,49 m/s2 

Calcul de la distance (x−x0 ) : 
On utilise l'équation de la 
cinématique indépendante du 
temps : v2−v02 =2⋅a⋅(x−x0 ).
02−52=2⋅(−0,5)⋅x
−25=−1⋅x
x=25 m Elle mettra 25 mètres pour s'arrêter.

Calcul du temps (t) : 
On utilise l'équation de 
l'accélération : 
a= v−v0 / t−t0.
−0,5=t0−5 
t= −5 / −0,5
t=10 s 
Elle mettra 10 secondes pour s'arrêter.

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ex14.py