stat2.py

Created by mailystrehel

Created on November 07, 2024

1.79 KB


Moyenne = somme(xi)/N
Variance S2(x)= x2-(x)2
Ecart-type S(x)=VS(x)2
S = EC
Coefficient de correlation  p = cov(xy)/(Sx*Sy)
Cov(x*y) = XY-X*Y
Coef p quand proche 1 ajustement lineaire ok
La methode des moindres carres permet lajustement dune serie
Droite de regression lineaire
P = a*x+b
a = cov(x , p)/S2(x)
loi N centre réduite (0 ;1)
E(z) = 0 Esperance

Qhi 2
P(-x=<X=<x)
-x = 0,05 
P(X=<x) = 0,05

P(X=<0) ,  X2 est nulle sur]-inf ; 0]
P(x=>0) = 1
Si ddl > 100 loi X2 donc loi N  N(ddl ; V2ddl)
Z=x-E(x)/S(x)
P(X = x) (x**n)p**x(1-p)**(n-x)
E(x) = np   moyenne

n=>30
np=>5
nq=>5
214
loi discrete ->loi continue
S inconnu & n=>30
Ica = [X  za/2*Sc/Vn ; X+za/2*Sc/Vn
Sc(corrige)n/(n-1) *S2
Table ecart Reduit
Amplitude = 2*za/2 * Sc/Vn

Intervalle de confiance   Proportion loi inconnue
n=>30
np=>5
n(1-p)=>5
Formulaire 
Application formule
za/2  a=Pourcentage de confiance si 95%->5%
tableau ecart réduit

intervalle de confiance Loi N
n<30
x=
S=connu
Za/2  a=(5%
Même table

Amplitude 
Prendre les 2 intervalle
I1 = [A ;B] -> B-A=Ampli
I2 = [A ; B] -> B-A=Ampli

Intervalle de confiance  loi Student
Sc = connu
S = inconnu
n<30
Loi N
t -> loi de student
ta/2 ; (n-1) -> a = %conf
Puis chercher dans table de student

Test validiter
Pop(ref)  u0 = connu  S = connu
Pop(etabli)  moyenne = inconnue    ecart type = inconnue
Ech  n=connue  moyenne= connu  S = inconnue
a=%conf
Bilat réduit a
Unilat augment 2a
n<30
S connu
X loi N
Test comparaison moyenne 
n 1=>30
n 2=>30
S connu
Corrige S2c = n/(n-1) * S21
Hypothese
H0   u0 = u1
H1   u0 > u1
Table ecart Reduit
Type du test uni=/bilat

S inconnu
n 2 =n 1<30
corrige S2c
1/3<S2c1/S2c2<3
Formule Sp et T
Loi student si ecart type + loi N
Si effectif theorique = (tot ligne*tot colonne)/tot general
Test X2
T = somme(Oi-Ci)2/Ci
Ddl + (nb ligne -1) * (nb colonne-1)

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