mat.py

Created on December 12, 2020
729 Bytes
# Type your text here
#
#e^a+b=e^a+e^b
#(e^a)^b=e^ab
#ln(ab)=ln(a)+ln(b)
#ln(a/b)=ln(a)-ln(b)
#ln(a^b)=b*ln(a)
#ln(1/a)=-ln(a)
#e^ln(a)=a
#ln(e^a)=a
#
#e^0=1
#ln(1)=0
#
#10^a+b=10^a*10^b
#(10^a)^b=10^ab
#log(ab)=log(a)+log(b)
#log(a/b)=log(a)-log(b)
#log(a^b)=b*log(a)
#log(1/a)=-log(a)
#10^log(a)=a
#log(10^a)=a
#
#10^0=1
#log(1)=0
#
#a^x=b = xln(a)=ln(b) = x=(ln(b)/ln(a))
#
#Dérivées:
#
#(e^x)'=e^x
#(e^kx)'=ke^kx
#(e^u)'=u'*e^u
#e^u=u'*e^u
#
#(ln(x))'=1/x
#(lnkx)'=1/x
#(ln(u))'= (u'/u)
#
#Primitve:
#f e^xdx=(e^x)ba=e^b-e^a
#f ke^xdx=k(e^x)ba=k(e^b-e^a)
#f u'e^u(x)dx=(e^u(x))ba=e^u(b)-
#e^u(a)
#
#f (1/x)dx=(ln(x))ba = ln(b)-ln(a)
#f (k/x)dx=kln(x)ba = k(ln(b)-ln(a))
#f (u'(x)/u(x))dx=(ln(ux))ba=ln(ub)-ln(ua)