jfet.py

Created by mailystrehel

Created on November 20, 2022

704 Bytes

Ig0=0

1.Statique
Id=Idss(1-Vgs/VgsOFF)^2
->Id0=Idss(1-Vgs0/VgsOFF)^2
->Id0/Idss=(1-Vgs0/Vgsoff)^2
->Racine(id0/Idss)= 1-Vgs0/Vgsoff 
deux solution une positive et une neg à cause de la racine
R(id0/Idss)+1= Vgs0/Vgsoff 
Vgs0=(R(id0/Idss)+1)*Vgsoff
Vgs0 tjrs négatif

Mailes à gauche et à droite

0=Rs.Id0+Vgs0+Rg.Ig0(0)
->Vgs0=-Rs.Id0

E=Rs.Id0+Vds+Rd.Id0
E=Vds0+(Rs+Rd)id0

x=Vgs0
y=Id0
y=-Rsy=(-1/Rs)*x

2.Dynamique
Gm=dId/dVgs
Polarisation
Gm=Idss2(-1/-VgsOff)(1-Vgs0/-Vgsoff)

ig=Y11.Vgs+Y12.Vds
id=Y21.Vgs+Y22.Vds

Y21=Gm
Y22=id/Vds

Exo:
Id0.(Rs1+Rs2)+Vgs0+Ig0.Rg=0

Vdd=Rd.Id0+Vds0+Id0(Rs2+Rs1)
Rd-Vds0-(Id0(Rs2+Rs1))/Id0

Vs/Ve=-Rd.GmVgs/Vgs(GmVgs+1)
Rs1=((-Rd.Gm/(Vs/Ve))-1)/Gm

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