equation_dissociation.py

Created by hicham-choukour

Created on May 24, 2024

2.19 KB


Les solutés apolaires ou peu polaires sont généralement solubles dans les solvants apolaires.
Ex : le diode est soluble dans le cyclohexane et peu soluble dans leau.

Al2(SO4)3(s)  2Al3+ + 3SO42-
AgNO3 (s)  Ag+ + No3-
Al(OH)3   Al3+  + 3OH- 
AlCl3 (s) Al3+    +  3Cl-   


Ca(NO3)2(s)  Ca2+ + 2No3-
CaCl2 (s)  Ca2+ + 2 Cl-
CaF2(s) Ca2+  + 2 F -
CaOH2(s)  Ca2+ + 2OH-
CoCl2 (s) Co2+  + 2Cl- 
CuCl2(s)  Cu2+ + 2 Cl   
CuI2(s)  Cu2+ + 2l-


FeCl3(s)  Fe3+ + 3Cl-
Fe(SO4(s))3   2 Fe3+ + 3 SO42-

H2SO4 (s) 2 H+  +  SO42- 

Li2CO32Li+ + CO32-

NaOH Na+  + OH- 
Na2SO4 (s) 2 Na+  + SO42- 
Na2CO3 2 Na+  + CO32- 
NaHCO3 Na+  + HCO3- 
NaCl(s)  Na+ + Cl chlorure de sodium (NaCl)
(NH4)2S2NH4+ + S2-

Mg(ClO4)2) Mg2+  + 2HClO4- 
MgCl2  Mg2+  + 2Cl- 


K2SO3 2K+ + SO32-
K2SO4 2K+ + SO42-

KMnO4 K+  + MnO4- 



AX (s)  A+  + X- 
[X]=n / V   en mol.L-1
n en mol
V en L

sulfate de sodium Na2SO4
                       Na2SO4 (s) 2 Na+  + SO42- 
EI : x=0          !    n              !      0     !     0 
EF : x=xmax  !    0              !      2n     !     n

[Na+]=2n / V  et [SO42-]=n / V  
[Na+]= 2 [SO42-]
--------------------------------------------------------------------------------------------------
AlCl3
                       AlCl3 (s) Al3+    +  3Cl-   
EI : x=0          !    n              !      0     !     0 
EF : x=xmax  !    0              !      n     !     3n

[Cl-]=3n / V  et [Al3+]=n / V  
[Cl-]=3 [Al3+]
--------------------------------------------------------------------------------------------------
 CoCl2
                       CoCl2 (s) Co2+  + 2Cl- 
EI : x=0          !    n              !      0     !     0 
EF : x=xmax  !    0              !      n     !     2n

[Co2+ ]=n / V  et [Cl-]=2n / V  
[Cl-]= 2 [Co2+]
--------------------------------------------------------------------------------------------------
 H2SO4
                       H2SO4 (s) 2 H+  +  SO42- 
EI : x=0          !    n              !      0     !     0 
EF : x=xmax  !    0              !      2n     !     n

[H+]=2n / V  et [SO42-]=n / V  
[H+]= 2 [SO42-]
--------------------------------------------------------------------------------------------------






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