chap5phyique.py

Created by gbbirdieputt

Created on March 08, 2024

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1er Newton
dans un referentiel considere comme 
galileen si le systeme etudie est isole
ou pseudo isole alors son mvtest rectiligne
uniforme ou au repos et reciproquement

Somme Fext=0 V->G=constante

2eme Newton
dans un referentiel considere comme
galileen la somme vectorielle des forces ext
appliques au systeme est egale au produit de la
masse de ce systeme par acceleration de son
centre d'inertie

Somme Fext=(m*(dv/dt))=m*a

3eme Newton
A et B 2 objets en interaction la force exercee
par A sur B est lopposee de la force de B sur A

Fa>b=-Fb>a

CHAMP DE PESANTEUR
p=mg
SommeF=ma
primitive de a=
   ax=0      vx=K1          vx=v0*cosa
at ay=-g = vt vy=gt+K2 (vt0=vy=v0*sina
   az=0  vz=K3              vz=0

primitive de v=
   vx=v0*cosa      yx=v0*cosa*t+K4                yx=0
vt vy=g*t+v0*sina = yt yy=(-1/2g)*t**2+v0*sina*t+K5 (yt0=yy=0
   vz=0            yz=K6                          yz=0  
    
    x=v0*cosa 
OMt y=(-1/2g)*t**2+v0*sina*t
    z=0
    
CHAMP ELECTRIQUE
F=qE
SommeF=ma=qE
a=qE/m
primitive de a=
   ax=0         vx=K1               vx=v0*cosa
at ay=(qE/m) vt vy=(-qE/m)+K2  (vt0=vy=v0*sina
   az=0         vz=K3               vz=0

primitive de v=  
   vx=v0*cosa                yx=v0*cosa*t+K4                    yx=0
vt vy=(-qE/m)*t+v0*sina = yt yy=(-qE/2m)*t**2+v0*sina*t+K5 (yt0=yy=0
   vz=0                      yz=K6                              yz=0
   
    x=v0*cosa 
OMt y=(-qE/m)*t**2+v0*sina*t
    z=0
    
Ec=1/2mv**2
Epp=mgz
Emeca=Ec+Epp

Wab(F)=F*AB*cosa
dEc(A>B)=Ec(B)-Ec(A)=SommeWab(F)
E=U/d
a=qU/dm

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