dm1_734_2019.py

Created by frederic-junier

Created on October 06, 2019

257 Bytes

Correction du DM 1 Retourne le plus petit entier n tel que l’amortissement total dépasse 100000 la somme empruntée. Cet entier représente le nombre de mensualités nécessaire pour rembourser l’emprunt.

def seuilBanqueA():
  n = 1
  while 200000 * (1.0025 ** n  - 1) <= 100000:
    n = n + 1
  return n
  
def seuilBanqueAV2():
  n = 1
  a = 500
  sa = a
  while sa <= 100000:
    a = a * 1.0025
    sa = sa + a 
    n = n + 1
  return n

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