m23.py

Created on February 02, 2025

510 Bytes

# Type your text here
1ere formule :ptoduit scalaire
uvect.vvect=0 si uvect=o et vvect=0
uvect.vvect=u*v*cos(u;v)
2 orthogo et projeté
si perpendiculaire alors ortho 90 deg
donc Uvec.Vvect =0
projete ab.ac=ab.ah ou H est le projete de c sur AB
3Carre scalaire / id remarq 
ou avec les identité remarq:
  u vect2=!!u!!2 car uvect.uvect = !!uvect!!*!!uvect!!*cos(u.u)=Uvect2
  u.v = 1:2((u+v)2-u2-V2)
  
4 analytique
avc les coordonée u.v =xx'+yy'
5 decomposer 
6  al kasi
a2=b2+c2-2bc*cos(A)

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m23.py