thermo2td5.py

Created by famille-bvc

Created on June 02, 2023

1 KB


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Moteur diesel :
  
  B_____C
  |     |
  |     |
  |     \
  \      \_____D
   \          |
    \__________A
    
cycle du moteur :
(w inverse de l'air sous la courbe)
AB : w>0 Q=0
BC : w<0 Q>0
CD : w<0 Q=0
DA : w=0 Q<0

expression du rendement : 
P = -Wcycle / Qbc

exprimer ceci en fonction des temp:
P = (Qab+Qbc+Qcd+Qda)/Qbc 
  = 1 + Qda/Qbc
  = 1 + 1/Y * (Ta-Td)/(Tc-Tb)

On a :
taux de compression = 21
taux de détente = 7
à 147km/h on a 4500tr/min
conso de 8L/100km

rendement théor avec Y=1.4 :
        1    21^-1,4 - 7^-1,4
P = 1 + __ + ________________
        1,4     1/7 - 1/21
  = 0,61
  
Masse de carburant injectée à
cycle à vitesse max:
  
1 cycle <-> 2 tours d'arbre
-> 2 * 60/4500 s
-> 2 * 60/4500 * 147/3600 km
-> ... * 147/3600 * 8/100 L
-> ... * 8/100 * 0,8 kg
 = 7.10^-5 kg
 = 70 mg
 
Puissance max :
  
on a pouvoir calor = 46.8 kj/g

      46,8.10^3 * 7.10^-2
Qsc = ___________________
            2*60/4500

=> w = Qsc*0.61 = 75kw
(0.61 = rendement)

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