metrologie2.py

Created by famille-bvc

Created on December 22, 2023

1.34 KB


Ve = 15V

1. Exprimer vA et vB en fonction de Ve et des
résistances.

R = RJ+DRJ

I1 = Ve/(R1+R2)
VA = R2/(R1+R2) * VE
VB = R/(R+R3) * Ve = (RJ+DRJ)/(RJ+DRJ+R3) *VE

2. Deduire lexpression de Vm.

Vm = VA-VB = VE[(R2/(R1+R2)) - ((RJ+DRJ)/(RJ+DRJ+R3))]

3. Au cas dequilibre du pont, exprimer la
resistance de la jauge (RJ + ΔRJ) en fonction des
resistances R1, R2 et R3.

equilibre => Vm = 0

R2/(R1+R2) = (RJ+DRJ)/(RJ+DRJ+R3)
-> R2(RJ+DRJ) + R2R3
  = R1(RJ+DRJ)+R2(RJ+DRJ)
-> RJ+DRJ = (R2R3)/R1

4. Reprenons lexpression de Vm et supposons que
R1=R2=R3=RJ=R ; exprimer Vm.

V'm = VE[(R'/(R'+R')) + ((R'+DR')/(R'+DR'+R'))]

= VE[1/2 - (R'+DR')/(2R'+DR')]
      2R'+DR'-2R'-2DR'
= VE[-----------------]
          4R'+2DR'
       -DR'
= VE(--------)
     4R'+2DR'


5. On donne DR'/R' = 0.05
= 0,05 ; calculer V'm.

V'm = -0.18V


/////////////////////////////////

Exprimer C(x) en fonction de E1, E2 , x, h et e.

(E : Signe qui ressemble la)

C(x)= E1S/e [1 + x/h * (E2/E1 - 1)]

Déduire les capacites minimales et maximales

|Zmin|= 1/C0w = (1)/(((E1*S)/(e)) * 2pif)

|Zmax|= 1/C1w = (1)/(((E2*S2)/(e)) * 2pif)

Donner lexpression de la tension de
mesure Vmes en fonction de x, h, E1, E2 et Vg.


             E2
           (---- -1)
             E1
(Vg/2)*[---------------]
         E2         2x
       (---- -1) + ----
         E1         h

During your visit to our site, NumWorks needs to install "cookies" or use other technologies to collect data about you in order to:

With the exception of Cookies essential to the operation of the site, NumWorks leaves you the choice: you can accept Cookies for audience measurement by clicking on the "Accept and continue" button, or refuse these Cookies by clicking on the "Continue without accepting" button or by continuing your browsing. You can update your choice at any time by clicking on the link "Manage my cookies" at the bottom of the page. For more information, please consult our cookies policy.