ex_barrage.py

Created on December 07, 2021

677 Bytes

Le barrage retient une quantité
de 1,2 milliards de m3 d'eau
a une hauteur de 129m

1 Calculez la masse d'eau en kg

1,2*10^9 m3=1,2*10^12 
dm3=1,2*10^12L =1,2*10^12kg

2 Calculez l'énergie potentielle
en J

EP=MGH=1,2*10^12kg*9,81*129
=1,52*10^15 J

3 Déduire le résultat en MWH

1,52*10^15/3600=4,2 *10^11 
WH=4,2 *10^5 MWH

le débit d'eau qv=300m3/s

4 Calculez le temps qu'il 
faudra pour vidercomplètement 
le barrage. Donner le résultat
en heure

t=Volume/Qv = 1,2*10^9/300 s
 =4*10^6 secondes
 soit 4*10^6/3600=1111,11 Heures
 soit 1111/24=48 Jours

5 Déduire la puissance
hydraulique produite par ce 
barrage 

pHydrau=4,2 *10^5/1111,11=378 MW

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ex_barrage.py