s2thermoexotypechap3echangeradiatif.py

Created by condouarthur

Created on June 02, 2024

785 Bytes


Exo type 1 
Surface plan i 
que vaut Fii 
0 car aucune flux thermique qui ne quitte la surface et al rejoint

Exo type :
  demi sphère: 
    Quel est le factueur de forme sachant que F12 = 1 car tout ce qui sort de 1 va vers 2 et F11 = 0 car surface plane
  Réciprocité : A1F12 = A2F21
  Donc F21 = F12*S1/S2 = 1/2
  F22 = 1/2 par somme F12 + F22 = 1
  
Exo type demi cylindre :
  F12 = 1 
  F11 = 0
  Réciprocité A1F12 = A2F21 soit 
  F21 = A1F12/S2 = 2 /pi
  F22 par somme soit F22 = 1-F21= pi-2 / pi

Puissance nette de Rayonnement est 
Q°ij = AiFijsigma(Ti^4-Tj^4)
Soit deux surfaces parallèles, on sait que T1 = 200°C et T2 = 50°C
on a L1=L2=D=1 Déterminer Q°12
Facteur de forme F12 = 0.2 
Ai = 1m2
Qij°=1*0.2*5.67e-8(150) = 444.6

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