# Type your text here
ForcedeLorentz:F=qEqv^BchampelectroE(D,M)=Q/4piEor^2uK->Mprgravita°A(M)=-Gmk/KM^2uK->MtravaildelaforceelecWA->B=-delt(Ep)=-q(V(B)-V(A))E=-gradV<=>dV=-E.dlLechampEdérivdupotVUnitésduchamp:V.m-11dipoleestrigidsi||p||=ctemomentdipolairep=qNPr>>NP:aproxdipolairedipelectropotV=p.ur/4piEor^2=pcosO/4piEor^2sidipolerigidEp=-p.EextetT=p^EextsinonrigideT=p^EextcylindreP=(M,ur,uO)etQ=(M,ur,uz)plsych=>E//ruladistribu°deschestinvparrotOettransOz=>Eaussi=>E=E(r)urthGintdoubl(E.dSext)=Qint/Eo=E(r)2pirhsir>Rdq=sigmadSE=sigmR/Eorur<Qint=oE=OdV=-E.dl=-E(r)drsir<=E=OdV=OV=cter>=dV=-sigmR/EordrV-Vo=-sigmR/Eoln(r/R)(onintègreentreRetr)sphèreP=(M,ur,uO)etQ=(M,ur,uphi)pldesydeschE//uretE=E(r)urthGintdoubl(E.dSext)=E(r)4pir^2sir>=RE=roR^3/3Eor^2urr<=RQint=ro4/3pir^3=>E=ro*r/3EourdV=-E.dl=-E(r)drsir>=RdV=-roR^3/3Eor^3dr=-Q/4piEor^2drenintégrantentreinfinietr=Q/4piEorpourr=RV(R)=roR^2/3Eosir<=RdV=-ror/3EodronintègreentreRetr=roR^2/3Eo*(3/2)planP=(M,ux,uz)etQ=(M,uy,uz)plsych=>E//uzladistribu°deschestinvpartransOxetOy=>Eaussi=>E=E(z)uzE(M')=-E(z)uz
th G
intdoubl(E.dSext)=Qint/Eo=2E(z)
si z>O Qint=sigmaS E=sigm/2Eo uz
< E=-sigm/2Eo uz
dV=-E.dl=-E(z)dz
si z>O V-Vo=-sigm/2Eo uz
condensateur plan
V2-V1 la diff de pot
entre les deux armatures dV=-E.dl et E=sigma/Eoux et dl=dxux
comme Q=Q1=sigmaS
Q1=C(V1-V2)
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