ed.py

Created on February 08, 2022

470 Bytes

y'=ay --> Ce^ax 
Si f et g sont deux solutionds de l’équa diff y’=ay alors f+g et kf sont 
également solutions 
y'=ay+b --> Ce^ax –b/a 
y'=ay+f -->y’=2y+x2 (sol particuliere, on derive on remplace on trrouve C) 
Soit a un nombre réel et f une fonction définie sur un intervalle I. Soit (E) 
l’équation dif y’=ay+f et g une sol particulliere de (E) sur I. Les solutions de 
(E) sur I  sont les fonctions xI--> Ce^ax + g(x), où C est une constanté réel.

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