autre.py

Created on March 22, 2024
1018 Bytes
A 25 degre:
Ke=1.0*10**-14
pKe=14.0

Ke=(H3O*)eq/c0
Ke=(HO-)eq/c0

pKe=-log(Ke)

Ke=10**-pKe

(H3O*)eq=10**-pH

(HO-)eq=Ke/(HO3+)eq

pH=-log(Ke/(HO-)eq)
pH=-log((H3O+)eq/c0)
c0=1

T=xf/xmax
Tf=10**-pH/C

Acide et Base faible:
  (faible si cette 
reaction est un equilibre
chimique, reaction non total
reaction limiter cad 
T superieur 1)
  Acide:
    HA+H2O=A-+H3O+
  Base:
    A-+H2O=HA+HO-
Exemple:
  HCI/Cl-
    
Acide et Base forte:
  (faible si cette 
reaction est total ou quasi
total cad T=1)
    Acide:
    HA+H2O(une fleche)A-+H3O+
    Base:
    A-+H20(une fleche)HA+HO-
Exemple:
  NaOH/Na+
  CH3O-/CH3OH
  
Trouver le concentration
en ion H3O+:
  (H3O+)f=C=n/V
  
Solution acide fort:  
pH=-log(C)
  C (inferieur)10**-2
  pH (superieur)0
  
Solution base forte:
  pH=pKe+log(C)
  
Exemple:
Acide chlorhydrique:
  H3O+/Cl-
Acide nitrique:
  H3O+/NO3-
Acide ethanoique:
  CH3COOH
  
soude ou hydroxyde de sodium:
  Na+/HO-
ammoniac:
  NH3
  

Ka=((H3O+)eq*(A-)eq)/(HA)eq

pKa= -log Ka

Ka=10**-pKa