# Type your text here si a/b et a/c alors a/kb+kpc* si a/b, alors a/a+B et a/a-b a==b[n] => n/(a-b) a==b[n] => a=b+kn si a==b[n] et b==c[n] alors a==c[n] si a==b[n] et b==c[n] alors * a==c[n] si a==b[n] et c==d[n]: - a+c==b+d[n] - a*c==b*c[n] - k*a==k*b[n] - a**p ==b**p[n]