physique0son0aide.py

Created by alten01

Created on March 05, 2023

779 Bytes


seloigner de la source sonore
mettre des bouchons doreille

determiner a quelle distance il doit
se deplacer pour avoir niveau dintensite
sonore L2=75dB
I=P/4pix**2
Calcul de P
P=I*4pi*x**2
calculer avec les conditions initiales
normalement
Calcul de x
P=10**L2/10*I0*4pi*r**2
x=sqrt(P/ 10**L2/10*I0*4pi)

f=1/T
3T=0.003s soit T=0.001s
f=1/0.001=1000Hz

interference destructive constructive

dioptrie=S2M-S1M=0
dioptrie=0*lambda=0
comme resultats egaux, interferences
constructives -> intensite
bien maximale a ce point

dioptrie=M1O,-M2O,=
(12+x)-(12-x)=2x
si intensite min on a interference
destructives
dioptrie=(2k+1)*lambda/2
Pour k=0: dioptrie=lambda/2
Dapres(1)et(2)on a 2x=lambda/2
soit x=lambda/4
c=lambda*f
lambda=c/f
x=c/f /4   =resultat en m

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