deduire_la_suite_vn.py

Created on October 13, 2024

449 Bytes

demontrer que la suite vn est geometrique 
de raison 0.98:
  vn+1=un+1-12500
  Vn+1=0.98un-12250
  Vn+1=0.98(un-12500)

exprimer pour tout n Vn en fonction de n:
  quel que soit n.vn=v0*0.98n
  soit vn=-1940*0.98**n
  
exprimer pour tout n Un en fonction de n:
  vn=un-12500 alors un=vn+12500
  donc 12500-1940*0.98**n
  
determiner la limte:
  comme 0<0.98<1 on sait que la limte
  de 0.98**n=0 donc limite
  de un=12500

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